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CA Foundation doubt

If 3^a = 5^b = 75^c, what is the value of ab - c(2a + b)?

Ch ratio , proportion , indices and logarithm. Question 34 which i posted

Ch ratio , proportion , indices and logarithm. Question 34 which i posted

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Asked by Sunidhi··1 answer

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  1. BrunoAI answerAI first answer — verify with your teacher

    Answer: (b) 0 Let 3^a = 5^b = 75^c = k. 1. Then 3 = k^(1/a), 5 = k^(1/b), 75 = k^(1/c). 2. Since 75 = 3 x 5 x 5, we get k^(1/c) = k^(1/a) x k^(2/b). 3. Equate the powers: 1/c = 1/a + 2/b = (b + 2a)/ab. 4. So ab = c(2a + b), which gives ab - c(2a + b) = 0. Tip: Q33, Q35 and Q36 use the same trick. Put everything equal to k and break the last base into prime factors.

Related questions

What is the shortcut for questions like 2^x = 3^y = 6^z?

Put each expression equal to k and use 6 = 2 x 3, which gives 1/z = 1/x + 1/y.

Which law of indices is used in these questions?

The product law, a^m x a^n = a^(m+n), is used to equate exponents once all bases are written as powers of the same k.

Can logarithms be used instead?

Yes, taking logs of each expression gives a log 3 = b log 5 = c log 75, which leads to the same relation.

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