CA Foundation doubt
How do I solve factorial sums like 1/7! + 1/8! = N/9! in Permutations and Combinations?
Can anyone explain how to solve this sum of p&c ch ?
Asked by Krupa··2 answers
CA Foundation doubt
Can anyone explain how to solve this sum of p&c ch ?
Asked by Krupa··2 answers
BrunoAI answerAI first answer — verify with your teacher
Trick: multiply both sides by the biggest factorial, then cancel. Q7: 1/7! + 1/8! = N/9! Multiply by 9!: - 9!/7! = 9 x 8 = 72 - 9!/8! = 9 N = 72 + 9 = 81, so option (a). Q8: 1/9! + 1/10! = x/11! Multiply by 11!: - 11!/9! = 11 x 10 = 110 - 11!/10! = 11 x = 110 + 11 = 121. That is not in the options, so (d) None of these. Key idea: n! = n x (n-1)!, so 9!/7! = 9 x 8.
Krupa
Thank you Bruno
0! is defined as 1. This keeps formulas like nPr and nCr valid when r = n or r = 0.
Write n! as n x (n-1) x (n-2)!, then cancel (n-2)!. The result is n(n-1).
No. In the CA Foundation syllabus, factorial is defined only for non-negative integers.
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