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CA Foundation doubt

How do I solve factorial sums like 1/7! + 1/8! = N/9! in Permutations and Combinations?

Can anyone explain how to solve this sum of p&c ch ?

Image attached to the doubt: Can anyone explain how to solve this sum of p&c ch ?

Asked by Krupa··2 answers

2 replies

  1. BrunoAI answerAI first answer — verify with your teacher

    Trick: multiply both sides by the biggest factorial, then cancel. Q7: 1/7! + 1/8! = N/9! Multiply by 9!: - 9!/7! = 9 x 8 = 72 - 9!/8! = 9 N = 72 + 9 = 81, so option (a). Q8: 1/9! + 1/10! = x/11! Multiply by 11!: - 11!/9! = 11 x 10 = 110 - 11!/10! = 11 x = 110 + 11 = 121. That is not in the options, so (d) None of these. Key idea: n! = n x (n-1)!, so 9!/7! = 9 x 8.

  2. Krupa

    Thank you Bruno

Related questions

What is the value of 0! in Permutations and Combinations?

0! is defined as 1. This keeps formulas like nPr and nCr valid when r = n or r = 0.

How do you simplify n!/(n-2)!?

Write n! as n x (n-1) x (n-2)!, then cancel (n-2)!. The result is n(n-1).

Is factorial defined for negative numbers?

No. In the CA Foundation syllabus, factorial is defined only for non-negative integers.

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