Can you check my answer on whether a partnership exists and allot marks to it?

SSheetal

Good

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BrunoAI answer

Your answer is correct: Ram is liable only for his share of Rs. 1,500. I'd give about 4.5 to 5 out of 6. What you did well: - Section 4 definition and the three essentials (agreement, sharing profits of a business, mutual agency) are written clearly. - The facts are applied neatly and the conclusion is right. Where you lost marks: 1. You did not cite Section 6 (mode of determining the existence of partnership). Its Explanation 1 says that sharing the gross returns of jointly owned property does not, by itself, make the owners partners. This is the key provision in the ICAI answer. 2. Add one line that Ram and Raheem are only co-owners of the flat, not partners, so there is no joint liability. 3. Minor point: keep "existence" and "Raheem" spelled correctly and the conclusion tidy.

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VVeer

1. Right side me log rule lagao: \(\frac{1}{2}(\log a + \log b)\) ban jayega \(\log(\sqrt{ab})\). 2. Dono taraf se \(\log \) hata do, toh bachega \(\frac{a+b}{3} = \sqrt{ab}\). 3. Ab dono side square karo, toh \((a+b)^2 = 9ab\) aa jayega. 4. Formula kholo: \(a^2 + b^2 + 2ab = 9ab\), yani \(a^2 + b^2 = 7ab\). 5. Bas ab poore equation ko \(ab\) se divide kar do, seedha \(\frac{a}{b} + \frac{b}{a} = 7\) mil jayega

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AAkshuuu

With pratice bro

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IIshaan· 3 found helpful

You should go for May 27 or September 27

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VVeer

• Set equal to \(k\). Let \(3^a = 5^b = 75^c = k\), which gives \(3 = k^{1/a}\), \(5 = k^{1/b}\), and \(75 = k^{1/c}\). • Factor \(75\). Since \(75 = 3 \times 5^2\), substitute the \(k\) values to get \(k^{1/c} = k^{1/a} \cdot (k^{1/b})^2\). • Equate exponents and simplify. Add the powers on the right to get \(\frac{1}{c} = \frac{1}{a} + \frac{2}{b}\). Cross-multiplying gives \(ab = c(2a + b)\), so \(ab - c(2a + b) = 0\).

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