Sum of n terms of the series 0.1 + 0.11 + 0.111 + … is a)1/9 {n – (1– (0.1)n)} b)1/9 {n – (1–(0.1)n)/9} c)n– 1 – (0.1)n/9 d)none of these

Rahul · 15 Mar 2024

0.1+0.11=0.21 now put in option n=2 and you will get sum upto 2nd place I.e.0.21

Rahul · 15 Mar 2024

B

charubala · 15 Mar 2024

How many places you are adding that no. You should substitute .... *

charubala · 15 Mar 2024

I used a calculator trick..... So step 1 add 0.1 + 0.11 .... So you will get the sum up to 2 places .... Now step 2 option testing method you can substitute 2 in place of n and check if the options are matching with the ans you got in step 1 ..... Note if you add up to 2 palaces substitute 2 ...or How many places you are adding that no. U should substitute that no. ....

Naveen · 15 Mar 2024

Any tip to solve

Naveen · 15 Mar 2024

How to solve this

charubala · 15 Mar 2024

Option b