The answer in module is11761.36 I dont know how

Himanshi, · 19 Aug 2025

₹500 end of each year 12 years (n=12) One year after → use n+1=13 A = 500 ×(1.1)^13-1 ----------------=11761.36 0.1

Himanshi, · 19 Aug 2025

Question padhte hi kaise samjhe: “End of each year → Ordinary annuity “Beginning of each year” → Annuity due “Immediately after last payment” → Normal (n) “One year after last payment” → Use (n+1)

Ekansh · 19 Aug 2025

Formula =. r ( (1+i)^n - 1 ) / i. 500 ( (1+0.1)^12 - 1 )/0.1 = 10692.1418 and after one year = 10692.1418 × 1.1 = 11761.36 ∆ (1.1) = ( 1 + i )