Someone plz solve this question

Khushi · 12 Aug 2025

Quartile deviation= .675xσ = .675x4= 2.7 (c) answer!!:)

Arpita · 11 Aug 2025

Thnks

Santosh · 11 Aug 2025

Let’s solve it step-by-step. We are given: Mean μ = 10 μ=10 (not needed for quartile deviation in normal distribution) Standard deviation σ = 4 σ=4 Formula for Quartile Deviation (Q.D.) in a normal distribution: Q . D . = Q 3 − Q 1 2 Q.D.= 2 Q 3 −Q 1 For a normal distribution: Q 1 = μ − 0.675 σ Q 1 =μ−0.675σ Q 3 = μ 0.675 σ Q 3 =μ+0.675σ So: Q 3 − Q 1 = μ + 0.675 σ ) − ( μ − 0.675 σ ) Q 3 −Q 1 =(μ+0.675σ)−(μ−0.675σ) Q 3 − Q 1 = 1.35 σ Q 3 −Q 1 =1.35σ Now, Q . D . = 1.35 σ 2 = 0.675 σ Q.D.= 2 1.35σ =0.675σ Substitute σ = 4 σ=4: Q . D . = 0.675 × 4 = 2.7 Q.D.=0.675×4=2.7 ✅ Correct answer: 2.70 (Option C)