Anyone know how to solve this ?

A · 6 Aug 2024

[-4,4] limits included

Parthiv · 4 Aug 2024

Since it is in root for it√(16-x²) to be real must greater than zero. i.e x²<16. -4

👀👀👀 · 4 Aug 2024

Ok 👍🏻 got it F(x) is minimum when x=4 And F(x) is maximum when x=0 Therefore c=[0,4]

Varshini. · 4 Aug 2024

0² is 0 and root of 16 is 4 so

Varshini. · 4 Aug 2024

Option verification maybe

👀👀👀 · 4 Aug 2024

How ?

Sanskruti · 4 Aug 2024

C option