How to find out the answer and what is the answer

Rohit · 23 Jun 2024

4^x = 5^y = 20^z -------> 4^x = k 4 = k^1/x 5^y = k 5 = k^1/y 20^z = k 20 = k^1/z --> let's write 4×5=20 So , we can write ... (k^1/x) × (k^1/y) = (k^1/z) Using property (from chapter 1) (1/x) + (1/y) = (1/z) (1/x) + (1/y) - (1/z) = 0 .. (answer)

Sheetal · 23 Jun 2024

b. 0