Log 64 to base √2 = x.... When written in exponential form it becomes √2^x =64... √2^x can be written as (2^1/2 )^x... As 2^6 is 64 out the value of x as 12.... So it becomes 12/2 =6.... And 2^6 is 64.....

CA Foundation doubt

Can anyone explain

Asked by Aditya8 Jun 2024358 views

6 answers

Vedant · 9 Jun 2024
Ans is. 12
Dhanu · 8 Jun 2024
Log 64 to base √2 = x.... When written in exponential form it becomes √2^x =64... √2^x can be written as (2^1/2 )^x... As 2^6 is 64 out the value of x as 12.... So it becomes 12/2 =6.... And 2^6 is 64.....
Shilpa · 8 Jun 2024
View attached PDF
Ꮐyꫝɴꫝ · 8 Jun 2024
View attached PDF
Aditya · 8 Jun 2024
Can you explain
Dhanu · 8 Jun 2024
12! If I'm not wrong

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