SI. = 10200-8500 => 1700 1700= 8500×12.5×t / 100 " t = 1.6 " Op(a) -> 1yr 7mnth [7mnth -> 7/12] 1+ (7/12). = 1.58333 Op(c). -> 1. 1/2 -> (1yr 6mnth). [1yr = 12 mnth .so half 6mnth] 1+(6/12). = 1.5 Approx opt {A} 1yr 7mnth is correct

But in book answer given is 1.7

Therefore, T = 1.6 i.e. 1 and half yrs

Amt- principal= SI 10200- 8500 = SI T = (SI × 100)/ (Rate × principal) T = (1700 × 100) / (12.5 × 8500)

CA Foundation doubt

Question number 7

Asked by Ankesh1 Jun 2024204 views

6 answers

Hairiya · 1 Jun 2024
SI. = 10200-8500 => 1700 1700= 8500×12.5×t / 100 " t = 1.6 " Op(a) -> 1yr 7mnth [7mnth -> 7/12] 1+ (7/12). = 1.58333 Op(c). -> 1. 1/2 -> (1yr 6mnth). [1yr = 12 mnth .so half 6mnth] 1+(6/12). = 1.5 Approx opt {A} 1yr 7mnth is correct
Ankesh · 1 Jun 2024
But in book answer given is 1.7
Aashish · 1 Jun 2024
(C)
Soniya · 1 Jun 2024
Therefore, T = 1.6 i.e. 1 and half yrs
Soniya · 1 Jun 2024
Amt- principal= SI 10200- 8500 = SI T = (SI × 100)/ (Rate × principal) T = (1700 × 100) / (12.5 × 8500)
Soniya · 1 Jun 2024
7. (c) 1 and half yrs

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