Maths module page no. 5.13 exercise 5(B) please explain me how to solve 6th que

Shaikh · 5 May 2024

Number of different things = 10 Number of times =4 Now as it is said that one particle thing always occur so it will reduce to selecting 9things from 3 things/ time Number of ways selecting 3 things out of 9 different things such that one particular thing always occur =⁹C = 9!/3!×6!=84 ³ 4th thing is fixed so number of ways for selecting 4th thing is 4!=24 So required number of ways=84×24=2016